ZIP files in a folder using Java Program
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Question / Problem
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This Java sample program demonstrates two things. 1. Zip files. 2. To list all the files in a folder
Most often, there is a need to zip files programmatically. In my case i had to automate the process of zipping and emailing the zipped file to the administrator at the end of every day
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Solution
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import java.io.*;
import java.util.zip.*;
public class Zip {
static final int BUFFER = 2048;
public static void main (String argv[]) {
try {
BufferedInputStream origin = null;
FileOutputStream dest = new
FileOutputStream("g:\\zip\\myfigs.zip");
ZipOutputStream out = new ZipOutputStream(new
BufferedOutputStream(dest));
//out.setMethod(ZipOutputStream.DEFLATED);
byte data[] = new byte[BUFFER];
// get a list of files from current directory
File f = new File(".");
String files[] = f.list();
for (int i=0; i<files.length; i++) {
System.out.println("Adding: "+files[i]);
FileInputStream fi = new
FileInputStream(files[i]);
origin = new
BufferedInputStream(fi, BUFFER);
ZipEntry entry = new ZipEntry(files[i]);
out.putNextEntry(entry);
int count;
while((count = origin.read(data, 0,
BUFFER)) != -1) {
out.write(data, 0, count);
}
origin.close();
}
out.close();
} catch(Exception e) {
e.printStackTrace();
}
}
}
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Applies to |
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Core Java
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Rank It |
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